Under root of all these numbers 999-1000x1001x1002+1 is
Nirmal K , 3 Years ago
Grade 11
Magical Mathematics[Interesting Approach]> Under root of all these numbers 999-1000x...
1 Answers
Armaan Arora
Last Activity: 3 Years ago
answer is c (1000999)
999*1000*1001*1002+1=10,01,99,89,98,001
and root of 10,01,99,89,98,001 is 1000999
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